Java.lang.Double.compareTo() Method

The java.lang.Double.compareTo() method compares two Double objects numerically. There are two ways in which comparisons performed by this method differ from those performed by the Java language numerical comparison operators (, =, ==, = ) when applied to primitive double values:

Following is the declaration for java.lang.Double.compareTo() method

public int compareTo(Double anotherDouble)

RETURN VALUE: This method returns the value 0 if anotherDouble is numerically equal to this Double; a value less than 0 if this Double is numerically less than anotherDouble; and a value greater than 0 if this Double is numerically greater than anotherDouble.

The following example shows the usage of java.lang.Double.compareTo() method.

package com.tutorialspoint;

import java.lang.*;

public class DoubleDemo {

   public static void main(String[] args) {

     // compares two Double objects numerically
     Double obj1 = new Double("8.5");
     Double obj2 = new Double("11.50");
     int retval =  obj1.compareTo(obj2);
     if(retval > 0) {
        System.out.println("obj1 is greater than obj2");
     else if(retval < 0) {
        System.out.println("obj1 is less than obj2");
     else {
        System.out.println("obj1 is equal to obj2");

Written by

Posted by fbrefere001 on Tuesday December 3, 2013